When light is incident on a surface, photoele | vedclass

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Question

(C) According to Einstein's photoelectric equation, $K_{max} = h
u - \Phi$, where $h
u$ is the energy of the incident photon and $\Phi$ is the work

Vedclass · Accepted Answer

The value of kinetic energy is equal to or less than a maximum kinetic energy.

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(C) According to Einstein's photoelectric equation, $K_{max} = h
u - \Phi$, where $h
u$ is the energy of the incident photon and $\Phi$ is the work function of the metal surface.Photoelectrons are emitted from different depths within the metal surface.Electrons emitted from the surface have the maximum kinetic energy $(K_{max})$.Electrons emitted from deeper layers lose some energy due to collisions before escaping the surface.Therefore, the kinetic energy of emitted photoelectrons ranges from $0$ to $K_{max}$.Thus, the kinetic energy of any photoelectron is always less than or equal to the maximum kinetic energy $(K \le K_{max})$.

When light is incident on a surface, photoelectrons are emitted. For photoelectrons:

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